JEE Main Chemistry question

The number of meso forms in the symmetric compound HOOC–CH(CH₃)–CH(OH)–CH(Cl)–CH(OH)–CH(CH₃)–COOH is

(A)3
(B)4Correct
(C)8
(D)16

Answer: (B)

Solution

The molecule is symmetric about its central CHCl carbon, with two pairs of equivalent-type stereocenters (the CH(CH₃) pair and the CH(OH) pair) flanking it. Systematically

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Question ID VK-139144