JEE Main Chemistry question

The total number of alkenes possible by dehydrobromination of 3-bromo-3-methylpentane using alcoholic KOH is

(A)1
(B)3Correct
(C)5
(D)7

Answer: (B)

Solution

CH₃CH₂–C(Br)(CH₃)–CH₂CH₃ is symmetric, so elimination toward either ethyl arm gives the same alkene, 3-methylpent-2-ene, as a mixture of its E and Z forms (2 stereoisomers).

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-139293