JEE Main Chemistry question

Which shows the easier electrophilic substitution in the ring?

(A)N-acetyl aniline
(B)C₆H₅NH₃Cl
(C)AnilineCorrect
(D)Nitrobenzene

Answer: (C)

Solution

Free aniline has its full nitrogen lone pair available to activate the ring by resonance. In N-acetyl aniline, that lone pair is partly delocalized into the amide carbonyl (less activating); in

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Question ID VK-139342