JEE Main Chemistry question

Stability order of C₆H₅–CH₂⁺ (I), CH₂=CH–CH₂⁺ (II), (CH₃)₃C⁺ (III), CH₂=CH⁺ (IV) is

Answer: (B)

Solution

Benzyl (I, resonance over the aromatic ring) is most stable, followed by tert-butyl (III, three-alkyl hyperconjugation/induction), then allyl (II,

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Question ID VK-139386