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JEE Main Chemistry question

ChemistrySome Basic Concepts of ChemistryJEE Main

4 g of a hydrocarbon on complete combustion gave 12.571 g of CO₂ and 5.143 g of water. What is the empirical formula of the hydrocarbon?

Answer: (C)

Solution

Moles CO₂ = 12.571/44 = 0.2857 mol = moles C. Moles H₂O = 5.143/18 = 0.2857 mol →

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Question ID VK-139524