JEE Main Chemistry question
If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is
Answer: (D)
Solution
Moles: C = 18.5/12 = 1.542, H = 1.55/1 = 1.55, Cl = 55.04/35.5 = 1.550, O = 24.81/16 =
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