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JEE Main Chemistry question

ChemistryStates of Matter (Gaseous & Liquid State)JEE Main

2.4 g of a hydrocarbon has a volume of 1 L at 1 atm and 127 °C. The hydrocarbon is

Answer: (D)

Solution

Using PV = nRT: n = PV/RT = (1×1)/(0.0821×400) = 0.0305 mol. Molecular

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Question ID VK-139546