JEE Main Chemistry question
Percentage composition of an organic compound is C = 10.06%, H = 0.84%, Cl = 89.10%. Which of the following corresponds to its molecular formula, if the vapour density is 60.0?
Answer: (B)
Solution
Moles: C=10.06/12=0.838, H=0.84/1=0.84, Cl=89.10/35.5=2.51. Ratio ≈ 1:1:3 → empirical formula CHCl₃
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