JEE Main Chemistry question
What is the empirical formula of a compound having 40% carbon, 6.66% hydrogen and 53.34% oxygen?
Answer: (C)
Solution
Moles: C=40/12=3.33, H=6.66/1=6.66, O=53.34/16=3.33. Ratio 1:2:1 → empirical formula CH₂O.
What is the empirical formula of a compound having 40% carbon, 6.66% hydrogen and 53.34% oxygen?
Moles: C=40/12=3.33, H=6.66/1=6.66, O=53.34/16=3.33. Ratio 1:2:1 → empirical formula CH₂O.