JEE Main Chemistry question
H₂C=O behaves as a(n)
Answer: (B)
Solution
Formaldehyde's carbonyl carbon is electron-poor and is attacked by nucleophiles in addition reactions — it is an electrophile.
H₂C=O behaves as a(n)
Formaldehyde's carbonyl carbon is electron-poor and is attacked by nucleophiles in addition reactions — it is an electrophile.