JEE Main Chemistry question

A straight-chain hydrocarbon has the molecular formula C₈H₁₀. The hybridization of the carbon atoms from one end of the chain to the other is sp³, sp², sp², sp³, sp², sp², sp, sp. The structural formula of the hydrocarbon would be

• (A)CH₃–C≡C–CH₂–CH=CH–CH=CH₂
• (B)CH₃–CH₂–CH=CH–CH=CH–C≡CH
• (C)CH₃–CH=CH–CH₂–C≡C–CH=CH₂
• (D)CH₃–CH=CH–CH₂–CH=CH–C≡CHCorrect