JEE Main Chemistry question
In 2-methylpropan-1-ol, the numbers of sp³, sp² and sp hybrid carbons are, respectively,
Answer: (C)
Solution
(CH₃)₂CH–CH₂–OH (isobutanol) has no double or triple bonds — all four carbons are sp³.
In 2-methylpropan-1-ol, the numbers of sp³, sp² and sp hybrid carbons are, respectively,
(CH₃)₂CH–CH₂–OH (isobutanol) has no double or triple bonds — all four carbons are sp³.