JEE Main Chemistry question

Chemistry Chemical Bonding and Molecular Structure JEE Main

In the hydrocarbon CH₃(C6)–CH(C5)=CH(C4)–CH₂(C3)–C(C2)≡CH(C1), the states of hybridisation of carbons 1, 3 and 5 respectively are

(A)sp, sp³, sp²Correct
(B)sp, sp², sp³
(C)sp³, sp², sp
(D)sp², sp, sp³

Answer: (A)

Solution

C1 (terminal alkyne carbon of C≡CH) is sp; C3 (–CH₂–, singly bonded on both

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Question ID VK-139869