JEE Main Chemistry question

On monochlorination of 2-methylbutane, the total number of optically active (chiral) monochloro products formed is

(A)2
(B)4Correct
(C)6
(D)8

Answer: (B)

Solution

Chlorinating 2-methylbutane, CH₃–CH(CH₃)–CH₂–CH₃, at C1 (or the equivalent branch methyl) gives 1-chloro-2-methylbutane, which has a stereocentre; chlorinating at C3 gives 2-chloro-3-methylbutane, which also has

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Question ID VK-139985