JEE Main Chemistry question

The correct order of ring-activating power of the groups –NH₂, –NHCOCH₃ and –CH₃ is

(A)–NH₂ > –NHCOCH₃ > –CH₃Correct
(B)–NH₂ < –NHCOCH₃ < –CH₃
(C)–NH₂ > –NHCOCH₃ < –CH₃
(D)–NH₂ < –NHCOCH₃ > –CH₃

Answer: (A)

Solution

–NH₂ donates its full lone pair into the ring and is the strongest activator; in –NHCOCH₃ (acetanilide), the nitrogen lone pair is partly delocalised into the amide

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Question ID VK-140156