JEE Main Chemistry question

Which of the following correctly represents the Reimer–Tiemann reaction?

(A)Phenol + CHCl₃/NaOH → 2-hydroxybenzaldehydeCorrect
(B)Phenol + NaOH/CO₂ → salicylic acid (this is the Kolbe–Schmitt reaction)
(C)A dialdehyde intermediate disproportionating under conc. NaOH to an alcohol + carboxylate (a Cannizzaro step, not the Reimer–Tiemann step itself)
(D)2,6-Dichlorophenol + NaOH (300 °C, 200 atm) → resorcinol (a Dow-type hydrolysis, not Reimer–Tiemann)

Answer: (A)

Solution

The Reimer–Tiemann reaction installs a –CHO group *ortho* to a phenolic –OH, via dichlorocarbene electrophilic attack on the phenoxide ring, giving salicylaldehyde — correctly

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Question ID VK-140369