JEE Main Chemistry question
How many 1° carbon atoms are present in a simple hydrocarbon of formula C₆H₁₄ that contains exactly one quaternary and one secondary carbon atom?
Answer: 4
Solution
The only C₆H₁₄ skeleton with one quaternary and one secondary carbon is 2,2-dimethylbutane, (CH₃)₃C–CH₂–CH₃: the quaternary carbon bears three methyl groups
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