JEE Main Chemistry question
Not in JEE Main or NEET syllabus
The edge length of a cubic unit cell of a metal having atomic weight 75u is 5 Å. If the density is 2 g cm, the radius of the metal atom is pm. [, ]
Answer: 212.5
Solution
First find : \dfrac{dN_Aa^3}{M}\dfrac{2×6.0×10^{23}×(5×10^{-8})^3}{75}\dfrac{2×6.0×10^{23}×1.25×10^{-22}}{75}\dfrac${1
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