In the sequence of reactions, C_2H_4 HBr X AgCN Y [ H _2/ Ni ] (reduction) Z, Compound Z is [AMU 2005]

JEE Main Chemistry question

In the sequence of reactions, , Compound is [AMU 2005]

(A)*N*-methyl ethanamineCorrect
(B)*N*-propylamine
(C)*N,N*-dimethylamine
(D)Ethyl cyanide

Answer: (A)

Solution

Ethylene + HBr → CHCHBr (). Silver cyanide, being covalent and ambident, reacts with alkyl halides through nitrogen to give an isocyanide (carbylamine): CHCHBr + AgCN → CHCHNC (,

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Question ID VK-142191