JEE Main Chemistry question
In the series, (starting material is ethylacetylene, HCC–CHCH; read as HCCH / terminal alkyne). The compound is [Pb. CET 2010]
- (A)CHCHCH=CH
- (B)CHCOCHCorrect
- (C)CHCHO
- (D)CHCHCHCHO
Answer: (B)
Solution
Acetylene (HCCH) is deprotonated by NaNH to the sodium acetylide, HCCNa (), which is alkylated by CHI to give propyne, HCC–CH
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Question ID VK-142194