JEE Main Chemistry question
Knowing the number and arrangement of carbon atoms in the aldehyde and ketone products of ozonolysis, the structure of the original alkene can be worked out. CH_2=CH–C(CH_3)=CH–CH_3 \xrightarrow[Zn/CH_3COOH]{O_3} gives which products?
Answer: (B)
Solution
Ozonolysis cleaves *each* C=C bond of a diene independently. For CH=CH–C(CH)=CH–CH, cleaving the first (C1=C2) double bond gives formaldehyde (HCHO, from the terminal =CH) and a ketone/aldehyde fragment at C2;
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