JEE Main Chemistry question

Chemistry Hydrocarbons JEE Main

Identify the reagent in the following sequence: HCCH CHCHC(=O)CH (via an intermediate alkyne alkylation and Markovnikov hydration).

(A)1. NaNH 2. CHCHBr, then HgSO/HSOCorrect
(B)(CHCOO)Hg
(C)OH
(D)HCOOH

Answer: (A)

Solution

Deprotonation of acetylene (NaNH) followed by alkylation with ethyl bromide builds but-1-yne, HCC–CHCH;

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-142448