(CH_3)_2C=CH–CH_2–CHO, on vigorous oxidation with hot alkaline KMnO_4, gives

JEE Main Chemistry question

(CH)C=CH–CH–CHO, on vigorous oxidation with hot alkaline KMnO, gives

(A)Acetone + malonic acidCorrect
(B)Acetone + propanoic acid
(C)Isopropanol + 1-propanol
(D)None of these

Answer: (A)

Solution

Hot, vigorous alkaline KMnO cleaves the C=C bond oxidatively (giving one ketone, from the fully substituted (CH)C= carbon, i.e. acetone) and also oxidises any aldehyde present all the way to a carboxylic

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Question ID VK-142488