(CH_3)_3C–CH=CH_2 (3,3-dimethylbut-1-ene) [] H _3 O ^+ A (major product). A is

JEE Main Chemistry question

(CH)C–CH=CH (3,3-dimethylbut-1-ene) (major product). is

(A)2,3-Dimethylbutan-2-olCorrect
(B)3,3-Dimethylbutan-2-ol
(C)2,2-Dimethylbutan-1-ol
(D)2,3-Dimethylbutane-2,3-diol

Answer: (A)

Solution

Protonation of the terminal alkene gives a secondary carbocation on C2, immediately adjacent to the quaternary C3 bearing three methyl groups. A 1,2-methyl shift from C3 to C2

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Question ID VK-142516