JEE Main Chemistry question

Which molecule undergoes free-radical (homolytic C–H abstraction) formation most readily?

(A)CHCHCH (propane)
(B)CHCHCHCH (*n*-butane)
(C)(CH)CH (isobutane)Correct
(D)(CH)CHCHCH (isopentane)

Answer: (C)

Solution

Bond-dissociation energy decreases from primary to secondary to tertiary C–H bonds, because the resulting radical is progressively stabilised by more adjacent alkyl

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-142614