R–CH=CH_2 [ C _2 H _5 OH ] Na/NH _3( l ) R–CH_2–CH_3. This dissolving-metal reduction of an alkene is called

JEE Main Chemistry question

R–CH=CH R–CH–CH. This dissolving-metal reduction of an alkene is called

(A)Clemmensen reduction
(B)Fischer–Speier reduction
(C)Birch (dissolving-metal) reductionCorrect
(D)Arndt–Eistert reduction

Answer: (C)

Solution

Sodium dissolved in liquid ammonia, with an alcohol as a proton source, delivers electrons and protons to reduce an unsaturated substrate via radical-anion

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Question ID VK-142622