JEE Main Chemistry question

Reductive ozonolysis (O, then Zn/HO) of a fused bicyclic alkene cleaves its ring double bond. What type of product results?

(A)The ring-opened dialdehyde product, consistent with cleavage at the ring double bondCorrect
(B)A fully aromatic product
(C)No reaction
(D)A triozonide without ring-opening

Answer: (A)

Solution

Ozonolysis cleaves the ring's double bond; because both carbons of that double bond belong to the same ring, cleaving it opens the ring rather than splitting the molecule into two separate

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Question ID VK-142705