3-Methylpent-2-ene, CH_3–CH=C(CH_3)–CH_2CH_3, reacting with HOCl, gives predominantly

JEE Main Chemistry question

3-Methylpent-2-ene, CH–CH=C(CH)–CHCH, reacting with HOCl, gives predominantly

Answer: (A)

HOCl forms a bridged chloronium ion across the double bond; water/hydroxide then opens it by attacking the more substituted

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Question ID VK-142722