JEE Main Chemistry question
Volume of 0.1 M required to oxidise 35 mL of 0.5 M solution is
Answer: (A)
Solution
The ionic equation is Cr_2O_7^{2-}+6Fe^{2+}+14H^+\to 2Cr^{3+}+6Fe^{3+}+7H_2O, so 1 mol reacts with 6 mol . Moles of mol, so
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account