JEE Main Chemistry question
The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile is added to its vapour pressure drops to 0.60 atm. The mole fraction of in the solution is
Answer: (B)
Solution
. The correct answer is option (B).
The vapour pressure of a pure liquid is 0.80 atm. When a non-volatile is added to its vapour pressure drops to 0.60 atm. The mole fraction of in the solution is
. The correct answer is option (B).