JEE Main Chemistry question

ChemistrySolutionsJEE Main

Following solutions at the same temperature will be isotonic:

Answer: (B)

Solution

Cane sugar (342 g/mol): mol/L. In (B), glucose (180 g/mol): mol/L — equal molarity and both non-electrolytes (), so isotonic. In (A) the glucose

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Question ID VK-143321