JEE Main Chemistry question

At , the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture of solution 'A' and 'B' boils at and 1 atm pressure, the amount of 'A' in the mixture is: (1 atm = 760 mm Hg)

• (A)50 mol per centCorrect
• (B)52 mol per cent
• (C)34 mol per cent
• (D)48 mol per cent