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JEE Main Chemistry question

ChemistrySolutionsJEE Main

The vapour pressure of pure benzene at a certain temperature is 650 mmHg. A non-volatile and non-electrolyte solid weighing 1.54 g is added to 26.00 g of benzene. The vapour pressure of the solution is 600 mmHg. The molecular weight of the solid substance is g .

Answer: 60.06

Solution

Moles benzene mol. Relative lowering $=(650-600)/650=0.07692≈

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Question ID VK-143473