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JEE Main Chemistry question

ChemistryElectrochemistryJEE Main

The cell reaction of a cell is Mg(s)+\mathrm{Cu^{2+}}(aq)\rightarrowCu(s)+\mathrm{Mg^{2+}}(aq). If the standard reduction potentials of Mg and Cu are and V respectively, the emf of the cell is

Answer: (C)

Solution

E_{cell} = E^\circ_{cathode}-E^\circ_{anode} = E^\circ_{Cu^{2+}/Cu}-E^\circ_{Mg^{2+}/Mg} = 0.34-(-2.37) = +2.71\ V.

Question ID VK-143599