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JEE Main Chemistry question

ChemistryElectrochemistryJEE Main

What is the value of ?

Given V, V

Answer: (A)

Solution

Here Cr is the anode and Fe the cathode: E^\circ_{cell} = E^\circ_{Fe^{2+}/Fe}-E^\circ_{Cr^{3+}/Cr} = -0.44-(-0.74) = +0.30\ V. Overall reaction

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Question ID VK-143642