The rusting of iron takes place as follows:
; V
; V
Calculate for the net process.

(A)-322 kJ molCorrect
(B)-161 kJ mol
(C)-152 kJ mol
(D)-76 kJ mol

Question

The rusting of iron takes place as follows: 2 H^+ +2e^-+ 12 O_2 H_2O (l); E^ =+1.23 V Fe^ 2+ +2e^- Fe (s); E^ =-0.44 V Calculate G^ for the net process.

Accepted Answer

(A)

JEE Main Chemistry question

Solution

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