JEE Main Chemistry question
The emf of the cell ( V, V) will be
Answer: (A)
Solution
At standard (1 M) conditions, E_{cell}=E^\circ_{cell}=E^\circ_{Cu^{2+}/Cu}-E^\circ_{Zn^{2+}/Zn}=0.34-(-0.76)=+1.10\ V.
The emf of the cell ( V, V) will be
At standard (1 M) conditions, E_{cell}=E^\circ_{cell}=E^\circ_{Cu^{2+}/Cu}-E^\circ_{Zn^{2+}/Zn}=0.34-(-0.76)=+1.10\ V.