JEE Main Chemistry question
What weight of copper will be deposited by passing 2 faradays of electricity through a solution of a Cu(II) salt?
Answer: (B)
Solution
: 2 F deposits exactly 1 mole (63.5 g) of copper.
What weight of copper will be deposited by passing 2 faradays of electricity through a solution of a Cu(II) salt?
: 2 F deposits exactly 1 mole (63.5 g) of copper.