JEE Main Chemistry question
Given , V, and , V, the emf of the cell \mathrm{Mg\,|\,Mg^{2+}\,||\,Cu^{2+}\,|\,Cu} is
Answer: (A)
Solution
E_{cell}=E^\circ_{Cu^{2+}/Cu}-E^\circ_{Mg^{2+}/Mg}=0.34-(-2.37)=2.71 V.
Given , V, and , V, the emf of the cell \mathrm{Mg\,|\,Mg^{2+}\,||\,Cu^{2+}\,|\,Cu} is
E_{cell}=E^\circ_{Cu^{2+}/Cu}-E^\circ_{Mg^{2+}/Mg}=0.34-(-2.37)=2.71 V.