JEE Main Chemistry question

ChemistryElectrochemistryJEE Main

For the reaction Zn(s)+\mathrm{Fe^{2+}}(aq)\rightarrow\mathrm{Zn^{2+}}(aq)+Fe(s) at 298 K, the cell potential is measured as V when and . The equilibrium constant for the reaction is

Answer: (D)

Solution

: , so V.

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Question ID VK-143960