JEE Main Chemistry question

ChemistryElectrochemistryJEE Main

At 298 K, the e.m.f. of the electrochemical cell will be V. (Given V)

Answer: 1.07

Solution

$=E^-Missing argument for \dfrac\dfrac{[\mathrm{Zn^{2+}}]}{[\mathrm{}

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Question ID VK-144147