JEE Main Chemistry question

1-Chlorobutane on reaction with alcoholic potash gives

(A)1-buteneCorrect
(B)1-butanol
(C)2-butene
(D)2-butanol

Answer: (A)

Solution

Alcoholic KOH promotes E2 elimination (dehydrohalogenation) rather than substitution. In 1-chlorobutane, CH_3CH_2CH_2CH_2Cl, the chlorine is on the terminal carbon, so there is only one

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Question ID VK-148072