JEE Main Chemistry question

When tetrahydrofuran is treated with excess HI, the product formed is

(A)1,4-diiodobutaneCorrect
(B)1,4-butanediol
(C)2-iodotetrahydrofuran
(D)4-iodo-1-butanol

Answer: (A)

Solution

Excess HI opens the cyclic ether of tetrahydrofuran at both carbon–oxygen bonds (acid-catalysed ring-opening followed by nucleophilic substitution of the resulting intermediate alcohol by a second equivalent of HI), converting both

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Question ID VK-148106