JEE Main Chemistry question

Optically active compound is:

(A)2-chloropropane
(B)2-chlorobutaneCorrect
(C)3-chloropentane
(D)None of these

Answer: (B)

Solution

2-Chlorobutane, CH_3-\overset{*}{C}H(Cl)-CH_2CH_3, has its C-2 bonded to four different groups (, , , ), making it a stereocentre and the molecule chiral/optically active. In 2-chloropropane, the

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Question ID VK-148170