JEE Main Chemistry question

1-Phenyl-2-chloropropane, on treating with alcoholic KOH, gives mainly:

(A)1-phenylpropeneCorrect
(B)2-phenylpropene
(C)1-phenylpropan-2-ol
(D)1-phenylpropan-1-ol

Answer: (A)

Solution

Alcoholic KOH brings about E2 dehydrohalogenation rather than substitution. Elimination of HCl from removes a -hydrogen either from the benzylic side or from the terminal methyl; removal from the

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Question ID VK-148203