JEE Main Chemistry question

2-Bromopentane is heated with potassium ethoxide in ethanol. The major product is:

(A)trans-pent-2-eneCorrect
(B)2-ethoxypentane
(C)pent-1-ene
(D)cis-pent-2-ene

Answer: (A)

Solution

Potassium ethoxide is a moderately strong, not-too-bulky base, so it promotes E2 elimination following Saytzeff's rule, favouring the more substituted (more stable) internal alkene, pent-2-ene, over the terminal pent-1-ene (ruling out C). Between the geometric

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Question ID VK-148211