JEE Main Chemistry question

-Propyl bromide reacts with ethanolic KOH to form:

(A)Propane
(B)PropeneCorrect
(C)Propyne
(D)Propyl alcohol

Answer: (B)

Solution

Ethanolic (alcoholic) KOH is a classic reagent for E2 dehydrohalogenation of alkyl halides. With -propyl bromide, CH_3CH_2CH_2Br, it removes HBr to form the terminal alkene: $CH_3CH_2CH_2Br

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Question ID VK-148293