In the reaction, CH_3C C-Na^+ + (CH_3)_2CHCl , the product formed is:

JEE Main Chemistry question

In the reaction, CH_3C\equiv C-Na^+ + (CH_3)_2CHCl \rightarrow, the product formed is:

(A)4-methyl-2-pentyneCorrect
(B)Propyne
(C)Propyne and propene
(D)None of these

Answer: (A)

Solution

Sodium propynylide (an acetylide, a strong carbon nucleophile) displaces the chloride from isopropyl chloride in an -type alkylation, forming a new carbon–carbon bond and extending the

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Question ID VK-148323