(A) CH_3OH/CH_3O^- methyl-substituted epoxide [H_2SO_4] CH_3OH (B). A and B are

JEE Main Chemistry question

. and are

(A)Both products from attack at the less-hindered carbon (basic conditions, ) and more-hindered carbon (acidic conditions, -like) respectively, giving the two different regiochemical methoxy-alcoholsCorrect
(B)Both identical products
(C)Both from attack only at the more-hindered carbon
(D)Both from attack only at the less-hindered carbon

Answer: (A)

Solution

Under basic/nucleophilic conditions (), epoxide ring-opening is an -type attack at the less-hindered carbon, giving one regiochemical outcome (); under acidic conditions (/), the epoxide is first protonated and opens

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Question ID VK-148591