JEE Main Chemistry question
Below are four proposed conversions: (i) CH_3-CH_3 \xrightarrow{Br_2/h\nu} \xrightarrow{aq.\ KOH} CH_3-CH_2OH (ii) CH_3-CH_2OH \xrightarrow{Cu,\ 300^\circ C} CH_3-CHO (iii) CH_3-CHO \xrightarrow{NaBH_4} CH_3-CH_2OH (iv) CH_3-CH_2-OH \xrightarrow{H_2/Ni} CH_3-CH_3. How many of the reagents shown are appropriate for the conversions as drawn?
Answer: 2
Solution
(i) is correct: photochemical bromination of ethane gives ethyl bromide, and aqueous KOH then substitutes bromide for hydroxide to give ethanol. (ii) is correct: hot copper dehydrogenates the primary alcohol to the aldehyde. (iii) is correct: reduces
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